Electrolysis | Chemistry for Majors (2024)

Learning Outcomes

  • Describe the process of electrolysis
  • Compare the operation of electrolytic cells with that of galvanic cells
  • Perform stoichiometric calculations for electrolytic processes

Electrochemical cells in which spontaneous redox reactions take place (galvanic cells) have been the topic of discussion so far in this chapter. In these cells,electrical work is done by a redox system on its surroundingsas electrons produced by the redox reaction are transferred through an external circuit. This final section of the chapter will address an alternative scenario in whichan external circuit does work on a redox systemby imposing a voltage sufficient to drive an otherwise nonspontaneous reaction, a process known aselectrolysis. A familiar example of electrolysis is recharging a battery, which involves use of an external power source to drive the spontaneous (discharge) cell reaction in the reverse direction, restoring to some extent the composition of the half-cells and the voltage of the battery. Perhaps less familiar is the use of electrolysis in the refinement of metallic ores, the manufacture of commodity chemicals, and theelectroplatingof metallic coatings on various products (e.g., jewelry, utensils, auto parts). To illustrate the essential concepts of electrolysis, a few specific processes will be considered..

The Electrolysis of Molten Sodium Chloride

Metallic sodium, Na, and chlorine gas, Cl2, are used in numerous applications, and their industrial production relies on the large-scale electrolysis of molten sodium chloride, NaCl(l). The industrial process typically uses aDowns cellsimilar to the simplified illustration shown in Figure 1.The reactions associated with this process are:

[latex]\text{anode:} \,\,\,\, 2\text{Cl}^- (l) \longrightarrow \text{Cl}_2 (g) + 2\text{e}^- [/latex]
[latex]\text{cathode:} \,\,\,\, \text{Na}^+ (l) + \text{e}^- \longrightarrow \text{Na} (l)[/latex]
[latex]\text{cell:} \,\,\,\, 2\text{Na}^+ (l) + 2\text{Cl}^- (l) \longrightarrow 2\text{Na} (l) + \text{Cl}_2 (g)[/latex]

The cell potential for the above process is negative, indicating the reaction as written (decomposition of liquid NaCl) is not spontaneous. To force this reaction,a positive potential of magnitude greater than the negative cell potentialmust be applied to the cell.

Electrolysis | Chemistry for Majors (1)

Figure1. Cells of this sort (a cell for the electrolysis of molten sodium chloride) are used in theDowns processfor production of sodium and chlorine, and they typically use iron cathodes and carbon anodes.

The Electrolysis of Water

Water may be electrolytically decomposed in a cell similar to the one illustrated in Figure 2. To improve electrical conductivity without introducing a different redox species, the hydrogen ion concentration of the water is typically increased by addition of a strong acid. The redox processes associated with this cell are

[latex]\text{anode:} \,\,\,\, 2\text{H}_2\text{O} (l) \longrightarrow \text{O}_2 (g)+ 4\text{H}^+ (aq) + 4\text{e}^- \,\,\,\,\, \text{E}^{\circ}_\text{anode} = +1.229\text{V}[/latex]
[latex]\text{cathode:} \,\,\,\, 2\text{H}^+ (aq) + 2\text{e}^- \longrightarrow \text{H}_2(g) \,\,\,\,\, \text{E}^{\circ}_\text{cathode} = 0\text{V}[/latex]
[latex]\text{cell:} \,\,\,\, 2\text{H}_2\text{O} (l) \longrightarrow 2\text{H}_2 (g) + \text{O}_2 (g) \,\,\,\,\, \text{E}^{\circ}_\text{cell} = -1.229\text{V}[/latex]

Again, the cell potential as written is negative, indicating a nonspontaneous cell reaction that must be driven by imposing a cell voltage greater than +1.229 V. Keep in mind thatstandardelectrode potentials are used to inform thermodynamic predictions here, though the cell isnotoperating under standard state conditions. Therefore, at best, calculated cell potentials should be considered ballpark estimates.

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Figure2.The electrolysis of water produces stoichiometric amounts of oxygen gas at the anode and hydrogen at the anode.

The Electrolysis of Aqueous Sodium Chloride

When aqueous solutions of ionic compounds are electrolyzed, the anode and cathode half-reactions may involve the electrolysis of either water species (H2O, H+, OH) or solute species (the cations and anions of the compound). As an example, the electrolysis of aqueous sodium chloride could involve either of these two anode reactions:

(i) [latex] 2\text{Cl}^−(aq) \longrightarrow \text{Cl}_2(g) + 2\text{e}^- \,\,\,\,\,\,\, \text{E}^\circ_{\text{anode}} = +1.35827 \text{V}[/latex]

(ii) [latex]2\text{H}_2\text{O}(l) \longrightarrow \text{O}_2(g) + 4\text{H}^+(aq) + 4\text{e}^-\,\,\,\,\,\,\,\text{E}^\circ_{\text{anode}}= +1.229 \text{V}[/latex]

The standard electrode (reduction) potentials of these two half-reactions indicate water may beoxidizedat a less negative/more positive potential (–1.229 V) than chloride ion (–1.358 V). Thermodynamics thus predicts that water would be more readily oxidized, though in practice it is observed that both water and chloride ion are oxidized under typical conditions, producing a mixture of oxygen and chlorine gas.

Turning attention to the cathode, the possibilities for reduction are:

(iii) [latex] 2\text{H}^+(aq) + 2\text{e}^− \longrightarrow \text{H}_2(g) \,\,\,\,\,\,\, \text{E}^\circ_{\text{cathode}}= 0 \text{V}[/latex]

(iv) [latex] 2\text{H}_2\text{O}(l) + 2\text{e}^− \longrightarrow \text{H}_2(g) + 2\text{OH}^-(aq) \,\,\,\,\,\,\, \text{E}^\circ_{\text{cathode}}= −0.8277 \text{V}[/latex]

(v) [latex] \text{Na}^+(aq) + \text{e}^− \longrightarrow \text{Na}(s) \,\,\,\,\,\,\, \text{E}^\circ_{\text{cathode}}= −2.71 \text{V}[/latex]

Comparison of thesestandardhalf-reaction potentials suggests the reduction of hydrogen ion is thermodynamically favored. However, in a neutral aqueous sodium chloride solution, the concentration of hydrogen ion is far below the standard state value of 1M(approximately 10-7M), and so the observed cathode reaction is actually reduction of water. The net cell reaction in this case is then

[latex]\text{cell: } 2\text{H}_2\text{O}(l) + 2\text{Cl}^-(aq) \longrightarrow \text{H}_2(g) + \text{Cl}_2(g) + 2\text{OH}^-(aq) \,\,\,\,\,\,\, \text{E}^\circ_{\text{cell}} = −2.186 \text{V}[/latex]
This electrolysis reaction is part of thechlor-alkali processused by industry to produce chlorine and sodium hydroxide (lye).

Electroplating

An important use for electrolytic cells is in electroplating. Electroplating results in a thin coating of one metal on top of a conducting surface. Reasons for electroplating include making the object more corrosion resistant, strengthening the surface, producing a more attractive finish, or for purifying metal. The metals commonly used in electroplating include cadmium, chromium, copper, gold, nickel, silver, and tin. Common consumer products include silver-plated or gold-plated tableware, chrome-plated automobile parts, and jewelry. We can get an idea of how this works by investigating how silver-plated tableware is produced (Figure3).

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Figure3. The spoon, which is made of an inexpensive metal, is connected to the negative terminal of the voltage source and acts as the cathode. The anode is a silver electrode. Both electrodes are immersed in a silver nitrate solution. When a steady current is passed through the solution, the net result is that silver metal is removed from the anode and deposited on the cathode.

In Figure 3, the anode consists of a silver electrode, shown on the left. The cathode is located on the right and is the spoon, which is made from inexpensive metal. Both electrodes are immersed in a solution of silver nitrate. Applying a sufficient potential results in the oxidation of the silver anode

[latex]\text{anode: } \text{Ag}(s) \longrightarrow \text{Ag}^+(aq) + \text{e}^−[/latex]

and reduction of silver ion at the (spoon) cathode:

[latex]\text{cathode: } \text{Ag}^+(aq) + \text{e}^− \longrightarrow \text{Ag}(s)[/latex]

The net result is the transfer of silver metal from the anode to the cathode. Several experimental factors must be carefully controlled to obtain high-quality silver coatings, including the exact composition of the electrolyte solution, the cell voltage applied, and the rate of the electrolysis reaction (electrical current).

Quantitative Aspects of Electrolysis

Electrical current is defined as the rate of flow for any charged species. Most relevant to this discussion is the flow of electrons. Current is measured in a composite unit called an ampere, defined as one coulomb per second (A = 1 C/s). The charge transferred,Q, by passage of a constant current, [latex]I[/latex], over a specified time interval, [latex]t[/latex], is then given by the simple mathematical product

[latex]Q =It[/latex]

When electrons are transferred during a redox process, the stoichiometry of the reaction may be used to derive the total amount of (electronic) charge involved. For example, the generic reduction process

[latex]\text{M}^{\text{n}+} (aq) + \text{ne}^- \longrightarrow \text{M} (s)[/latex]

involves the transfer ofnmole of electrons. The charge transferred is, therefore,

[latex]Q =nF[/latex]

whereFis Faraday’s constant, the charge in coulombs for one mole of electrons. If the reaction takes place in an electrochemical cell, the current flow is conveniently measured, and it may be used to assist in stoichiometric calculations related to the cell reaction.

You can view the transcript for “What Is Electrolysis | Reactions | Chemistry | FuseSchool” here (opens in new window).

Example 1:Converting Current to Moles of Electrons

In one process used for electroplating silver, a current of 10.23 A was passed through an electrolytic cell for exactly 1 hour. How many moles of electrons passed through the cell? What mass of silver was deposited at the cathode from the silver nitrate solution?

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Check Your Learning

Aluminum metal can be made from aluminum ions by electrolysis. What is the half-reaction at the cathode? What mass of aluminum metal would be recovered if a current of 25.0 A passed through the solution for 15.0 minutes? Assume the yield is 100%.

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Example 2:Time Required for Deposition

In one application, a 0.010-mm layer of chromium must be deposited on a part with a total surface area of 3.3 m2 from a solution of containing chromium(III) ions. How long would it take to deposit the layer of chromium if the current was 33.46 A? The density of chromium (metal) is 7.19 g/cm3.

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Check Your Learning

What mass of zinc is required to galvanize the top of a 3.00 m × 5.50 m sheet of iron to a thickness of 0.100 mm of zinc? If the zinc comes from a solution of Zn(NO3)2 and the current is 25.5 A, how long will it take to galvanize the top of the iron? The density of zinc is 7.140 g/cm3.

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Key Concepts and Summary

Nonspontaneous redox processes may be forced to occur in electrochemical cells by the application of an appropriate potential using an external power source—a process known as electrolysis. Electrolysis is the basis for certain ore refining processes, the industrial production of many chemical commodities, and the electroplating of metal coatings on various products. Measurement of the current flow during electrolysis permits stoichiometric calculations.

Key Equations

  • [latex]Q = I \times{t} = n\times{F}[/latex]

Try It

  1. Identify the reaction at the anode, reaction at the cathode, the overall reaction, and the approximate potential required for the electrolysis of the following molten salts. Assume standard states and that the standard reduction potentials in Standard Electrode (Half-Cell) Potentialsare the same as those at each of the melting points. Assume the efficiency is 100%.
    1. CaCl2
    2. LiH
    3. AlCl3
    4. CrBr3
  2. What mass of each product is produced in each of the electrolytic cells of the previous problem if a total charge of 3.33 × 105 C passes through each cell? Assume the voltage is sufficient to perform the reduction.
  3. How long would it take to reduce 1 mole of each of the following ions using the current indicated? Assume the voltage is sufficient to perform the reduction.
    1. Al3+, 1.234 A
    2. Ca2+, 22.2 A
    3. Cr5+, 37.45 A
    4. Au3+, 3.57 A
  4. A current of 2.345 A passes through the cell shown in Figurefor 45 minutes. What is the volume of the hydrogen collected at room temperature if the pressure is exactly 1 atm? Assume the voltage is sufficient to perform the reduction. (Hint: Is hydrogen the only gas present above the water?)
  5. An irregularly shaped metal part made from a particular alloy was galvanized with zinc using a Zn(NO3)2 solution. When a current of 2.599 A was used, it took exactly 1 hour to deposit a 0.01123-mm layer of zinc on the part. What was the total surface area of the part? The density of zinc is 7.140 g/cm3. Assume the efficiency is 100%.

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Glossary

electrolysis: process using electrical energy to cause a nonspontaneous process to occur

electrolytic cell: electrochemical cell in which electrolysis is used; electrochemical cell with negative cell potentials

electroplating: depositing a thin layer of one metal on top of a conducting surface

overpotential: difference between the theoretical potential and actual potential in an electrolytic cell; the “extra” voltage required to make some nonspontaneous electrochemical reaction to occur

Electrolysis | Chemistry for Majors (2024)

FAQs

How to solve electrolysis questions? ›

Calculating the Current Required
  1. Find the quantity of substance produced/or consumed in moles.
  2. Write the equation for the half-reaction taking place.
  3. Calculate the number of moles of electrons required.
  4. Convert the moles of electrons into coulombs of charge.
  5. Calculate the current required.

What is electrolysis answers? ›

electrolysis, process by which electric current is passed through a substance to effect a chemical change. The chemical change is one in which the substance loses or gains an electron (oxidation or reduction).

What is the formula for solving electrolysis? ›

Formula and Explanation: The mass (m) of a substance liberated in electrolysis can be calculated using the formula m = (Q × M) / (n × F), where M is the molar mass of the substance (in grams per mole), n is the number of moles of electrons involved in the redox reaction at the electrode, and F is the Faraday constant ( ...

How to do half equations in electrolysis? ›

Writing half equations
  1. Write down the ion and the product that will form at the electrode, with an arrow in between them. For example: Cl ⁻ → Cl2
  2. Use coefficients to balance the atoms on both sides of the equation. 2Cl⁻ → Cl2
  3. Use electrons to balance the charges on both sides of the equation. 2Cl ⁻ → Cl2 + 2e⁻

How painful is electrolysis? ›

You'll feel a sharp sting or temporary warmth as each hair follicle is treated. How much the process hurts depends on how you react to pain and the area being treated.

Is electrolysis good or bad? ›

Electrolysis is very safe. Very slight risks of infection (from an unsterile needle) or scarring exist if the electrolysis is not done correctly. These risks are very low if you choose a certified, professional electrolysis practice. You may have a slight reddening of the skin during or right after treatment.

How to study electrolysis? ›

To understand electrolysis, students need to have a basis of knowledge of cations and anions. Then, they must be able to distinguish between oxidation and reduction reactions, and which groups undergo which kind of reaction.

How does electrolysis work for dummies? ›

How does electrolysis work? The basic principle of electrolysis is to split water into oxygen and hydrogen with the help of electricity. The splitting occurs in two partial reactions that take place at the two electrodes – cathode (-) and anode (+) – in the electrolysis cell.

What is basic electrolysis? ›

Electrolysis is the passing of a direct electric current through an electrolyte which is producing chemical reactions at the electrodes and decomposition of the materials. The main components required to achieve electrolysis are an electrolyte, electrodes, and an external power source.

What makes electrolysis faster? ›

Pure water has an electrical conductivity about one-millionth that of seawater. Efficiency is increased through the addition of an electrolyte (such as a salt, an acid or a base) and electrocatalysts.

How to solve a question on electrolysis? ›

The first thing to do is to work out how many coulombs of electricity flowed during the electrolysis. Now put the numbers in: 1 mol of electrons is 1 faraday. So, if 96500 coulombs give 108 g of silver, all you have to do is to work out what mass of silver would be produced by 60 coulombs.

What is the best solution for electrolysis? ›

In general, an aqueous solution of caustic potash or soda is used as the electrolyte for water electrolysis. At equal concentrations, the conductiyity of caustic potash solutionis higher than that of caustic soda solution.

How do you find Z in electrolysis? ›

Z= Equivalent weight of the substance/96500 coulombs. The equivalent weight of the substance can be computed using the weight of the substance deposited (W gramme) after passing a specific amount of electricity (Q coulombs), i.e. Equivalent weight = W/Q * 96500.

What is the equation for the electrolysis experiment? ›

Cathode : 2 H 2 O l + 2 e - → H 2 g + 2 OH - aq Anode : 2 H 2 O l → O 2 g + 4 H + aq + 4 e -

How many seconds are required to produce 4.00 g of aluminum metal from the electrolysis of molten AlCl3 with an electrical current of 12.0 A? ›

Final answer: The time required to produce 4.00 g of aluminum from the electrolysis of molten AlCl3 with an electrical current of 12.0 A is approximately 3.57 x 10^3 seconds using Faraday's law of electrolysis.

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